Question

When 425g of lead pellets are added to a graduated cylinder the water level rises from 25.0mL to 62.5mL so what is the density of the lead pellets?

Answer 1

Displaced volume :

62.5 mL - 25.0 mL => 37.5 mL

Mass = 425 g

Therefore:

D = m / V

D = 425 / 37.5

D =  11.33 g/mL