Respuesta :
Explanation:
In this case, we need to divide two number where
First number, [tex]n_1=9\times 10^{-5}[/tex]
Second number, [tex]n_2=3\times 10^{-9}[/tex]
[tex]\dfrac{n_1}{n_2}=\dfrac{9\times 10^{-5}}{3\times 10^{-9}}[/tex]
We know that, 3 × 3 = 9
So, [tex]\dfrac{n_1}{n_2}=\dfrac{3\times 10^{-5}}{10^{-9}}[/tex]
Since, [tex]\dfrac{a^x}{a^y}=a^{x-y}[/tex]
Also, [tex]a^x.a^y=a^{x+y}[/tex]
Here, [tex]\dfrac{10^{-5}}{10^{-9}}=a^{-5-(-9)}=10^4[/tex]
[tex]\dfrac{n_1}{n_2}=3\times 10^{4}[/tex]
So, on dividing two numbers we get [tex]3\times 10^{4}[/tex]. Hence, this is the required solution.