Answer:
The second number in the sequence is 81.
Step-by-step explanation:
The sum of 4 consecutive integers is 326.
Let us assume that the first number is x. So the next numbers would be,
[tex]=x+1,x+2,x+3[/tex]
Sum of these number would be,
[tex]=x+(x+1)+(x+2)+(x+3)[/tex]
As it is given as 326, so
[tex]\Rightarrow x+(x+1)+(x+2)+(x+3)=326[/tex]
[tex]\Rightarrow x+x+1+x+2+x+3=326[/tex]
[tex]\Rightarrow 4x+6=326[/tex]
[tex]\Rightarrow 4x=326-6[/tex]
[tex]\Rightarrow 4x=320[/tex]
[tex]\Rightarrow x=80[/tex]
Hence, the second number (x+1) will be 81.