Question

what is the mass (in grams) of 9.27x1024 molecules of methanol(CH3OH)

Answer 1

Moles of methanol = 9.27x10^24/6.02x10^23 = 15.398 moles.

Mass of methanol = moles of methanol x molar mass of methanol
                               = 15.398 x 32.042
                               = 493.38 grams.

Hope this helps!

Answer 2

Answer:  493 grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text{Avogadro's number}}=\frac{9.27\times 10^{24}}{6.023\times 10^{23}}=15.4moles$

1 mole of $CH_3OH$ weighs = 32 g

15.4 moles of $CH_3OH$ weigh = $\frac{32}{1}\times 15.4=493g$

Thus mass of $9.27\times 10^{24}$ molecules of methanol weigh 493 grams.