Question

sandy is upgrading her internet service . Fast internet charges $60 for installation and $50.45 per month. Quick internet has free installation but charges $57.95 per months. write an equation that can be used to find the number of months at which the internet service would cost the same and solve the equation.

Answer 1

Let's let x equal the number of months that payment is made.
$60 is constant, because it is only charged once.
Let's let y equal the total cost for x amount of months.

For fast internet:
y=50.45x+60

For quick internet:
y=57.95x

The equations will equal each other when the payment has reached the same amount.
50.45x+60=57.95x 

Answer 2

Answer:

For fast internet:

y=50.45x+60

For quick internet:

y=57.95x

Step-by-step explanation:

Let's let x equal the number of months that payment is made.

$60 is constant, because it is only charged once.

Let's let y equal the total cost for x amount of months.

The equations will equal each other when the payment has reached the same amount.

50.45x+60=57.95x