Well,
for Heterozygous short-hair (Hh) X heterozygous short-hair (Hh), after
you put it in the Punnet square, you get HH, Hh, Hh, and hh. So the
genotype is simply the different combinations you see here. So HH =
homozygous dominant. Hh=heterozygous and hh is homozygous recessive. You
have 1 HH, 2 Hh, and 1 hh. So genotypic ratio would be 1:2:1 for
homozygous dominant: heterozygous: homozygous recessive
Phenotypic ratio here would be 3:1 since HH and the two Hh's have a big H
and show the dominant trait. Only 1 (hh) shows the recessive trait. hope this helps
