Question

3r+p=-8 and 2r + p = 22 2r+p=22

Answer 1

(3r+p=-8) + (2r + p = 22)
Multiply second equation by -1
(3r+p=-8) + (-2r - p = -22)
Subtract 2r from 3r while subtracting p from p and -8 from -22
Final Answer: r= -30

3r+p=-8
Subsititue -30 for r
3(-30)+p=-8
Multiply -30 by 3
-90+p=-8
Add 90 to both sides
Final Answer: p=82

And so the point of intersection on the graph would be (-30,82)

Answer 2

we can eliminate p
multiply 2nd equation by -1 and add to first

3r+p=-8
-2r-p=-22 +
1r+0p=-30

r=-30
sub back

2r+p=22
2(-30)+p=22
-60+p=22
add 60 both sides
p=82



r=-30
p=82