HELP{

Which conclusion about f(x) and g(x) can be drawn from the table?

The functions f(x) and g(x) are reflections over the x-axis.

The functions f(x) and g(x) are reflections over the y-axis.

The function f(x) is a decreasing function, and g(x) is an increasing function.

The function f(x) has a greater initial value than g(x).

HELP Which conclusion about fx and gx can be drawn from the table The functions fx and gx are reflections over the xaxis The functions fx and gx are reflections class=

Respuesta :

Answer: The correct conclusion is(B) The functions f(x) and g(x) are reflections over the y-axis.

Step-by-step explanation: Two functions f(x) and g(x) are given as follows:

[tex]f(x)=2^x,~~~~~~~g(x)=\left(\dfrac{1}{2}\right)^x.[/tex]

We know that if f(-x) = g(x), then the functions are reflections over Y-axis and if - f(x) = g(x), then the functions are reflections over X-axis.

We have,

[tex]f(-x)=2^{-x}=\left(\dfrac{1}{2}\right)^x=g(x),\\\\-f(x)=-2^x\neq g(x).[/tex]

So, the function g(x) is a reflection of f(x) over Y-axis.

The graph of f(x) and g(x) are drawn in the attached file. From there, it is clear that the functions are reflections over Y-axis, not reflections over X-axis.

So, options (A) is incorrect and option (B) is correct.

From the table, we have

[tex]f(-2)=\dfrac{1}{4},~~f(-1)=\dfrac{1}{2},~~f(0)=1,~~f(1)=2,~~f(2)=4,\\\\g(-2)=4,~~g(-1)=2,~~g(0)=1,~~g(1)=\dfrac{1}{2},~~g(2)=\dfrac{1}{4}.[/tex]

So, as the value of 'x' increases, the value of f(x) increases and value of y(x) decreases.

Therefore, f(x) is an increasing function and g(x) is a decreasing function. So, option (C) is incorrect.

Also, we have

[tex]f(0)=g(0)=1.[/tex]

So, both the functions have same initial value. So, option (D) is also incorrect.

Thus, the correct conclusion is (B) The functions f(x) and g(x) are reflections over the y-axis.

Ver imagen ColinJacobus

Answer:

The correct answer is B) The functions f(x) and g(x) are reflections over the y-axis.

Step-by-step explanation:

Hope this helps! :)

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