Question

Students in Mrs. Anderson’s health class are learning about how exercise affects your heart rate. Twelve students ran around the school track for different lengths of time. Then they measured their heart rates in beats per minute. Heart Rate Record Minutes Heart Rate (bpm) 7 121 8 136 7 122 4 96 3 90 6 120 7 118 4 98 2 84 5 110 7 118 8 128 Find the correlation coefficient of the data. Round to the nearest hundredth

Answer 1

Answer:

While resting, his heart rate is at 60 bpm. After sprinting, his heart rate is at 130bmp. The difference is 130 - 60 = 70

Step-by-step explanation:

i hope this helps

Answer 2

The correlation coefficient of the given data about time and heart rates is 0.98.

What is correlation coefficient?

A correlation coefficient is a statistical measure of the degree to which changes to the value of one variable expect change to the value of another.

How to calculate correlation coefficient?

We have been given time and heart rates of students in Mrs. Anderson's health class and we have to find the value of correlation coefficient.

The formula by Karl Pearson to calculate correlation coefficient is as under:

Correlation coefficient=

=∑(x-x bar)(y-y bar)/$\sqrt{sum(x-x bar)^{2} } \sqrt{sum(y-y bar)^{2} }$

We have to calculate figures required to fill in the formula which are:

∑(x-x bar)(y-y bar)=350

∑$(x-x bar)^{2}$=44.67

∑$(y-y bar)^{2}$=2872.25

Correlation coefficient=350/$\sqrt{44.67} \sqrt{2872.25}$

=350/6.68*53.59

=350/357.98

=0.977

After rounding off to nearest hundred it will be 0.98.

Hence the correlation coefficient of the data about time and heart rate is 0.98.

Learn more about correlation coefficient at https://brainly.com/question/4219149

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