Question

For what value of k will the relation R = {(2k+1, 3), (3k−2, −6)} not be a function?

Answer 1

For the relation to not to be a function we need the same value of x in (x,y) that gives off different values (y).

• 2k+1= 3k-2
• 2k-3k = -2-1
• -k = -3
• k = 3

Now plugging in the value of k,

• (2 x 3+1 ,3) =( 7,3)
• (3 x 3-2,-6) = (7,-6)

hence , the relation won't be function if k would be equal to 3

Answer 2

If domain becomes equal the relationship won't be a function

• 2k+1=3k-2
• 3k-2k=1+2
• k=3

value of k is 3