Question

Campbell's soup is creating a new soup label. if a can has a height of 6 in and a diameter of 4 in, how much material does campbell need for each soup label ?

Answer 1

Assuming the soup label covers the entire surface of the can, we solve for surface area. S.A. = 2pi*r^2  + pi*d*h = 8pi + 24pi = 32pi

32pi

Answer 2

The amount of material required for creating a soup label is 100.53 inches.

This is obtained by calculating the total surface area of the soap label which is cylindrical.

The total surface area of a cylinder:

The total surface area of the cylinder= surface area of CSA +surface area of LSA

I.e.,

TSA=2πrh+2πr²

      =2πr(h + r)

Calculation:

Given that,

The soap has a height of h=6 in and a diameter of d=4 in

So, the radius r=d/2

⇒ r=4/2=2

On substituting all these in the TSA formula,

TSA=2π×2(6+2)

      =4π×8

      =100.53 inches

Therefore, the material required for creating a soap label is 100.53 inches

Refer to more total surface area problems here:

https://brainly.com/question/1020784

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