Volume of the drill bit is equals to [tex]2,106\pi mm^{3}[/tex].
What is volume?
" Volume is defined as the total space occupied by a three dimensional object enclosed in it. It is measured in cubic unit."
Formula used
Volume of the cone = [tex]\frac{1}{3} \pi r^{2}h[/tex]
Volume of the cylinder =[tex]\pi r^{2}h[/tex]
r = radius of the cone / cylinder
h = height of the cone / cylinder
According to the question,
Given,
Radius of the cylinder = 9 mm
Radius of the cone = 9 mm
Height of the cone = 24 mm
Height of the cylinder = 18 mm
Substitute the values in the formula to obtained the required volume,
Volume of the cone [tex]= \frac{1}{3} \pi (9^{2})(24)[/tex]
[tex]= \pi (81)(8)\\=648\pi mm^{3}[/tex]
Volume of the cylinder [tex]= \pi (9^{2} )(18)[/tex]
[tex]=1458\pi mm^{3}[/tex]
Required Volume of the drill pit
= Volume of the cone + Volume of the cylinder
[tex]= (648\pi + 1458\pi )mm^{3} \\= 2106\pi mm^{3}[/tex]
Hence, Option(B) is the correct answer.
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