Question

A Cu/Cu2+ concentration cell has a voltage of 0.21 V at 25 ∘C . The concentration of Cu2+ in the cathode is 1.6×10−3 molL−1 .
What is the concentration of Cu2+ in the anode?

Answer 1

For a Cu/Cu2+ concentration cell has a voltage of 0.21 V at 25 ∘C, the concentration  is mathematically given as

c1=2.7*10^6.77m

What is the concentration of Cu2+ in the anode?

Generally, the equation for the Chemical reaction  is mathematically given as

Cu---->cu  +2^e    O

2e+Cu+2  ---->Cu    R

Therefore

$Ecell=\frac{0.0591}{n}log(c2/c1)\\\\0.25=\frac{0.0591}{2}log(1.6*10^{-3}/c1)$

c1=2.7*10^6.77m

In conclusion, the concentration is

c1=2.7*10^6.77m

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