Question

How can you find Find critical numbers for f(x) = x3 + 6x2 − 15x

Answer 1

Answer:

$x$-5, and $x$1

Step-by-step explanation:

f ($x$) = 3$x{2}$ + 12$x$ - 15

0= 3($x$$2$ + 4$x$ -5)

0= 3($x$ + 5) ( $x$ - 1)

[$x$+5=0] $x$= -5

[$x$-1=0] $x$= 1

hope it helped <3