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  • 19-04-2022
  • Mathematics
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1/secA+tanA = 1-sinA/cosA

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Аноним Аноним
  • 19-04-2022

Answer:

Below.

Step-by-step explanation:

1 / secA+tanA =  1 / [1/cosA+sinA/cosA))]

= 1/ [(1 + sinA)/cosA]

= cosA/(1+sinA)

Now check if this is identical to 1-sinA/cosA:

1-sinA/cosA = cosA/(1+sinA)

Cross multiply:

(1-sinA)(1+sinA) = cos^2A

1 - sin^2A = cos^2A

sin^2A + cos^2A = 1  

This is a known idenity.

So the original identity is true.

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