Question

345.50 grams of C6 H12 O6 = how many mol C6H12O6 ? - (MM=180.16g/mol).
100.0grams of O2 = how many mol O2? - (MM=32.00g/mol).
14.37 moles of AgNO3 = how many grams AgNO3? - (MM= 169.87g/mol).

Answer 1

Answer:

0.56 M

Explanation:

We are given;

Mass of glucose solute is 50.50 g

Volume of solution is 500 mL

We are required to calculate the concentration of glucose.

We need to know that, molarity is the concentration of a solution in moles per liter.

Molarity = Number of moles ÷ Molar mass