Question

A line passes through the point (–6, –2), and its y-intercept is (0, 1). What is the equation of the line that is perpendicular to this line and passes through the point (2, 3)?

Answer 1

Step-by-step explanation:

Gradient = y2-y2/x2-x1

= 1-(-2) / 0-(-6)

= 1/2

m1 × m2 = -1

1/2 × m2 = -1

m2 = -2

y= mx+c

(3)=(-2)(2) + c

c=7

°y= -2x +7