Question

50 POINTS! GIVING BRAINLIEST!

1. Given triangle ABC, where
2. A cable is attached to a pole 10 meters high. If the other end is attached to the ground 8 meters from the base of the pole. How long is the cable?

Answer 1

Answer:

the cable is  2\sqrt{41} meters long

Step-by-step explanation:

after drawing out the lengths given, you can see that you need to find the hypotenuse of a triangle with legs 10 and 8 meters long.

10^2+8^2=164

sqrt of 164 is $2\sqrt{41}$

Answer 2

Answer:

$2\sqrt{41}\: \sf m$ = 12.81 m (nearest hundredth)

Step-by-step explanation:

This can be modeled as a right triangle, with:

• height = 10 ft
• base = 8 ft

The length of the cable is the hypotenuse.

Using Pythagoras' Theorem: $a^2+b^2=c^2$

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

$\implies 8^2+10^2=c^2$

$\implies 164=c^2$

$\implies c=\sqrt{164}$

$\implies c=\sqrt{4 \cdot 41}$

$\implies c=\sqrt{4} \sqrt{41}$

$\implies c=2\sqrt{41}\: \sf m$

Therefore, the length of the cable is $2\sqrt{41}\: \sf m$ = 12.81 m (nearest hundredth)