kauggue1828 kauggue1828

18-04-2022
Chemistry

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How would you correctly prepare 125 mL of a 0.30M solution of copper(II) sulfate (CuSO4) from a 2.00M solution of CuSO4?

Respuesta :

jsimpson11000 jsimpson11000

22-04-2022

Answer:

see below

Explanation:

.3 M/L ( .125 L) = .0375 mole required

.0375 mole / 2 mole / l = .01875 l required

take 18.75 ml of the 2.0 solution then dilute it to 125 ml

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