I need to solve for “x” and then for “y”.
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Step-by-step explanation:
[tex]13 - 4y = 1 - y(opposite \: angles \: of \: a \: parallelogram \: are \: equal) \\ 13 - 4y = 1 - y \\ - 4y + y = 1 - 13 \\ - 3y = - 12 \\ y = \frac{ - 12}{ - 3} \\ y = 4 \\ \\ 7x - 3 = 6x + 3(opposite \: angles \: of \: a \: parallelogram \: are \: equal) \\ 7x - 3 = 6x + 3 \\ 7x - 6x = 3 + 3 \\ x = 6 \\ x = 6 \: \: \: \: \: y = 4[/tex]