Answer:
2nd option
Step-by-step explanation:
the nth term of a geometric sequence is
[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]
where a₁ is the first term and r the common ratio
here a₁ = 64 and r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{32}{64}[/tex] = [tex]\frac{1}{2}[/tex] , then
[tex]a_{n}[/tex] = 64 [tex](\frac{1}{2}) ^{n-1}[/tex]
