Question

use the discriminate to determine how many solutions this equation has -8x^2-8x-2=0

Answer 1

Answer:

One solution

Step-by-step explanation:

Discriminant

$\textsf{Discriminant}:b^2-4ac}\quad\textsf{when}\:ax^2+bx+c=0$

$\textsf{If}\quad b^2-4ac=0 \implies \textsf{one solution}$

$\textsf{If}\quad b^2-4ac > 0 \implies \textsf{two solutions}$

$\textsf{If}\quad b^2-4ac < 0 \implies \textsf{no solutions}$

Given equation:

$-8x^2-8x-2=0$

Swap sides:

$\implies 8x^2+8x+2=0$

Using discriminant:

$\implies b^2-4ac=8^2-4(8)(2)=0$

Therefore, there is one solution

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Proof

$8x^2+8x+2=0$

Divide both sides by 2:

$\implies 4x^2+4x+1=0$

Separate the middle term:

$\implies 4x^2+2x+2x+1=0$

Factor the first two terms and the last two terms separately:

$\implies 2x(2x+1)+1(2x+1)=0$

Factor out the common term $(2x+1)$:

$\implies (2x+1)(2x+1)=0$

Therefore:

$\implies 2x+1=0$

$\implies x=-\dfrac12$

Thus proving there is one solution.

Answer 2

• -8x²-8x-2=0

Here

• a=-8
• b=-8
• c=-2

Discriminate

• D=b²-4ac
• D=(-8)²-4(-8)(-2)
• D=64-64
• D=0

Roots are equal hence one solution