Question

Hannah is solving a quadratic equation in the form ax^2+ bx + c = 0
She has got to this point in her working out.
x = 3 +/- root 29 / 2
Find the values of a, b and c for the equation Hannah is solving.

Answer 1

A quadratic equation is represented by the form ax^2+ bx + c = 0

The values of a, b and c are 1, -3 and -5, respectively

How to determine the values of a, b and c?

The solution is given as:

$x = \frac{3 \pm \sqrt{29}}2$

The solution to a quadratic equation is represented as:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

By comparing $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ and $x = \frac{3 \pm \sqrt{29}}2$, we have:

-b = 3

So, b = -3

Also, we have:

2a = 2

So, a = 1

Also, we have:

b² - 4ac = 29

Substitute values for a and b

(-3)² - 4 * 1 * c = 29

This gives

9 - 4c = 29

Subtract 9 from both sides

-4c = 20

Divide by -4

c = -5

Hence, the values of a, b and c are 1, -3 and -5, respectively

Read more about quadratic equations at:

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