A) tan
B) tan^2
C) 1
D) -1
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Answer:
A) [tex]\tan \theta[/tex]
Step-by-step explanation:
[tex] \frac{\sin \theta}{ \sqrt{1 - { \sin}^{2} \theta } } \\ \\ = \frac{\sin \theta}{ \sqrt{ { \cos}^{2} \theta } } \\ \\= \frac{\sin \theta}{{ { \cos} \theta } } \\ \\ = \tan \theta[/tex]