Question

3. The weight of cell phones is normally distributed. The mean weight of a sample of 300 cell phones is 112 grams, with a standard deviation of 2 grams. With a 95% confidence level, determine
the maximum error of estimate
18.99%
22.63%
1.31%
29.73%

Answer 1

The maximum error of estimate with a sample of 300 cell phones is 29.73%

Determining maximum error estimate

The formula for calculating the maximum error of the estimate is expressed as:

ME = √0.25/n

n is the total sample

Given the following parameters

n = 300

Substitute into the formula to have:

ME = √0.25/n

ME = √0.25/300
ME = 0.2973
ME = 29.73%

Hence the maximum error of estimate with a sample of 300 cell phones is 29.73%

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