Question

any help would be appreciated.​

Answer 1

Answer:

10.4

Step-by-step explanation:

cosine rule=$a^{2}=b^{2} +c^{2} -2bc*cosa$

                $(2\sqrt{3}) ^{2}=(x+2)^{2} +x^{2} -2(x+2)x*cos60\\12=x^{2} +4x+4+x^{2} -2x^{2} -4x*\frac{1}{2}\\2x-8=0\\x=4\\Area=\frac{1}{2}absinc\\ = \frac{1}{2}*6*4*sin60\\\\ =6\sqrt{3}\\=10.4(3 sig.fig)$