Question

here are 16 sweets in a bowl.
4 of the sweets are blackcurrant.
5 of the sweets are lemon.
7 of the sweets are orange.
unna, Ravi and Sam cach take at random one sweet from the bowl.
Jork out the probability that the 5 lemon sweets are still in the bowl.

Answer 1

Answer:

61/112.

Step-by-step explanation:

For 5 lemon sweets to be in the bowl the 3 taken  must be from the 4 blackcurrent and/or 7 orange sweets.

First work out the probability of having a lemon in one of the 3 picks:

Prob (Taking 3  lemons) = 5/16 * 4/15* 3/14 =  60/3360 = 1/56.

Prob (Taking 2  lemons and 1 blackcurrent) = 5/16*4/15*4/14 =  1/42

There are 3 ways of doing this so Probab) = 3/42 = 1/14.

Prob (Taking 1  lemon and 2 blackcurrent) = 5/16*4/15*3/14 = 1/56.

There are 3 ways of doing this so Prob = 3/56.

Prob (Taking 2  lemons and orange) = 5/16*4/15*7/14 = 140/3360 = 1/24.

There are 3 ways of doing this so Prob) = 3/24 = 1/8.

Prob (Taking 1  lemon and 2 orange) = 5/16*7/15*6/14 =  1/16

There are 3 ways of doing this so Prob = 3/16.

Therefore the probability of have 1 or more lemons in one of the 3 picks

= 1/56 + 1/14 + 3/56 + 1/8 + 3/16

=  51/112

and the probability of NOT having a lemon in one of the 3 picks

= 1 - 51/112

=  61/112.