Respuesta :
1/8x - 49/8...u can factor out 1/8
1/8(x - 49)
u can even check ur answer by distributing the 1/8 thru the parenthesis
1/8(x - 49) = 1/8 * x - 1/8 * 49 = 1/8x - 49/8 (correct)
1/8(x - 49)
u can even check ur answer by distributing the 1/8 thru the parenthesis
1/8(x - 49) = 1/8 * x - 1/8 * 49 = 1/8x - 49/8 (correct)
ANSWER
[tex] \frac{1}{8} x - \frac{49}{8} = \frac{1}{8} (x - 49)[/tex]
EXPLANATION
We want to factor
[tex] \frac{1}{8} [/tex]
out of
[tex] \frac{1}{8} x - \frac{49}{8} [/tex]
We need to rewrite the above expression to obtain,
[tex] \frac{1}{8} x - \frac{49}{8} = \frac{1}{8} x - \frac{1}{8} \times 49[/tex]
We can see clearly now that there is a factor of
[tex] \frac{1}{8} [/tex]
common to both terms.
We take this factor out to obtain,
[tex] \frac{1}{8} x - \frac{49}{8} = \frac{1}{8} (x - 49)[/tex]
[tex] \frac{1}{8} x - \frac{49}{8} = \frac{1}{8} (x - 49)[/tex]
EXPLANATION
We want to factor
[tex] \frac{1}{8} [/tex]
out of
[tex] \frac{1}{8} x - \frac{49}{8} [/tex]
We need to rewrite the above expression to obtain,
[tex] \frac{1}{8} x - \frac{49}{8} = \frac{1}{8} x - \frac{1}{8} \times 49[/tex]
We can see clearly now that there is a factor of
[tex] \frac{1}{8} [/tex]
common to both terms.
We take this factor out to obtain,
[tex] \frac{1}{8} x - \frac{49}{8} = \frac{1}{8} (x - 49)[/tex]