Respuesta :
well.. so many folks caught a cold
so many off that total, recovered,
keep in mind that, the folks who recovered
are just a fraction of the ones who were
sick
so... simply subtract the "recovered" polynomial,
from the "caugh cold" polynomial, namely
[tex]\begin{cases} 8t-5t^2+t^3\impliedby &\textit{caught a cold}\\ \textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\ \cfrac{5-t^2+1}{5t^3}\impliedby &recovered \end{cases} \\ \quad \\\ [8t-5t^2+t^3]-\left[ \cfrac{5-t^2+1}{5t^3} \right]\implies \textit{still sick}[/tex]
so many off that total, recovered,
keep in mind that, the folks who recovered
are just a fraction of the ones who were
sick
so... simply subtract the "recovered" polynomial,
from the "caugh cold" polynomial, namely
[tex]\begin{cases} 8t-5t^2+t^3\impliedby &\textit{caught a cold}\\ \textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\ \cfrac{5-t^2+1}{5t^3}\impliedby &recovered \end{cases} \\ \quad \\\ [8t-5t^2+t^3]-\left[ \cfrac{5-t^2+1}{5t^3} \right]\implies \textit{still sick}[/tex]
The number of people who caught a col is 8t-5t^2+t^3,. A9nd the number of people who recovered are t-t^2+1/5t^3.