Respuesta :

Not totally sure but the answer might be 14 units
the perimeter of the triangle, will be the lengths of all segments,
making it up, so.. find the lengths of segments AB, BC and CA,
and sum them up
[tex]\textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &A({{ 1}}\quad ,&{{ 1}})\quad % (c,d) &B({{ 7}}\quad ,&{{ 1}})\\ &B({{ 7}}\quad ,&{{ 1}})\quad % (c,d) &C({{ 1}}\quad ,&{{ 9}})\\ &C({{ 1}}\quad ,&{{ 9}})\quad % (c,d) &A({{ 1}}\quad ,&{{ 1}})\\ \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}[/tex]
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