Respuesta :
the perimeter of the triangle, will be the lengths of all segments,
making it up, so.. find the lengths of segments AB, BC and CA,
and sum them up
[tex]\textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &A({{ 1}}\quad ,&{{ 1}})\quad % (c,d) &B({{ 7}}\quad ,&{{ 1}})\\ &B({{ 7}}\quad ,&{{ 1}})\quad % (c,d) &C({{ 1}}\quad ,&{{ 9}})\\ &C({{ 1}}\quad ,&{{ 9}})\quad % (c,d) &A({{ 1}}\quad ,&{{ 1}})\\ \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}[/tex]
making it up, so.. find the lengths of segments AB, BC and CA,
and sum them up
[tex]\textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &A({{ 1}}\quad ,&{{ 1}})\quad % (c,d) &B({{ 7}}\quad ,&{{ 1}})\\ &B({{ 7}}\quad ,&{{ 1}})\quad % (c,d) &C({{ 1}}\quad ,&{{ 9}})\\ &C({{ 1}}\quad ,&{{ 9}})\quad % (c,d) &A({{ 1}}\quad ,&{{ 1}})\\ \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}[/tex]