Question

Given the quantities a= 9.7 m, b= 4.2 s, c= 69 m/s, what is the value of the quantity d = a^3/(cb^2)?

Answer 1

Answer = a^3 / c.b^2

A = (9,7m)^(3) / 69m/s×(4,2s)^(2)

A = 912,673m^(3)/ 69m/s ×17,64s^2

A = 912,673m^(3) / 1.217,16m.s

A = 0,749838147 m^(2)/s

Or

A = 7,5 × 10^(-1) m^(2)/s

Answer 2

a³ / c.b² is the value of the quantity.

How to find the value of the quantity d = a^3/(cb^2)?

The value refers to the worth of each digit depending on where it lies in the number. We calculate it by multiplying the place value and face value of the digit.

Given,

A = (9,7m)³ / 69m/s×(4,2s)²

A = 912,673m³)/ 69m/s ×17,64s²

A = 912,673m³ / 1.217,16m.s

A = 0,749838147 m/s²

Or

A = 7,5 × 10^(-1) m/s²

Quantity is defined as an amount, measure, or number. An example of quantity is how many apples are in a barrel.

Learn more about quantity here: brainly.com/question/251701

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