Answer:
The solution is [tex]\frac{3(-1\pm\sqrt2)}{4}[/tex]
Step-by-step explanation:
Given the equation [tex](4x + 3)^2 = 18[/tex]
we have to find the solution of the given equation.
[tex](4x + 3)^2 = 18\\\\16x^2+9+24x=18\\\\16x^2+24x-9=0\\\\\text{The solution is calculated by discriminant rule}\\\\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\=\frac{-24\pm\sqrt{576+576}}{32}\\\\=\frac{-24\pm\sqrt{2(576)}}{32}\\\\=\frac{-24\pm24\sqrt{2}}{32}\\\\=\frac{3(-1\pm\sqrt2)}{4}[/tex]
hence, the solution is [tex]\frac{3(-1\pm\sqrt2)}{4}[/tex]
