Respuesta :

Answer:

Option A is correct.

The missing justification is: Transitive property

Step-by-step explanation:

Given:  [tex]\angle A \cong \angle B[/tex] ,   [tex]\angle C \cong \angle B[/tex]

Symmetric property of equality states the if for all real values of x , y

if x =y then, y =x.

Then, by symmetric property of equality:

we can write  [tex]\angle C \cong \angle B[/tex] as

[tex]\angle B \cong \angle C[/tex]

Transitive property of equality states that if we have the two things that are equal to each other and the second thing is equal to a third thing.

i.e, if a =b and b =c

then a =c

By transitive property of equality:

if  [tex]\angle A \cong \angle B[/tex] and [tex]\angle B \cong \angle C[/tex]

then;

[tex]\angle A \cong \angle C[/tex]                      ......[1]

Congruent angle states that the angles have exact the same measure

Therefore, by definition of congruent angles in [1] we have;

[tex]m\angle A = m \angle C[/tex]

Ver imagen OrethaWilkison

Answer:

∠A ≅ ∠C (transitive property)

Step-by-step explanation:

Given : Some statements

We have to choose the correct justification for the missing justification from the given options.

Consider ,

Since, given ∠A ≅ ∠C and  ∠C ≅ ∠B  

then ,      ∠B ≅ ∠C (BY SYMMETRIC PROPERTY)  

Also,

Using transitive property ,

If A= B and B = C then A = C  

Thus, ∠A ≅ ∠C and  ∠C ≅ ∠B  

Then ∠A ≅ ∠C (transitive property)

Thus, m∠A = m∠C (definition of similar triangles.)

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