Answer: It will take 2[tex]\frac{2}{5}[/tex] minutes to crawl the given distance
Step-by-step explanation:
Given :Ant crawls at the rate 2[tex]\frac{1}{6}[/tex] ft /min
=[tex]\frac{12+1}{6}[/tex] ft
=[tex]\frac{13}{6}[/tex] ft
Distance: 5[tex]\frac{1}{5}[/tex] ft
=[tex]\frac{25+1}{5}[/tex] ft
=[tex]\frac{26}{5}[/tex] ft
Time taken =[tex]\frac{Distance}{Speed}[/tex]
=[tex]\frac{26/5}{13/6}[/tex]
[tex]\frac{26*6}{5*13}[/tex]
Dividing numerator and denominator by 13
=[tex]\frac{12}{5}[/tex]
=2[tex]\frac{2}{5}[/tex] min
