Respuesta :
Using E=hν where h is Planck's constant and v is the frequency of the photon. In the question above,the wavelenght is given so we can find the frequency of the photon using c=λν. c is a constant =3*10^8 so frequency is equal to
(3*10^8)/0.135*10^-9. Then use ur frequency in the eqn above using h 6.626*10^-34
(3*10^8)/0.135*10^-9. Then use ur frequency in the eqn above using h 6.626*10^-34
Answer:
884.9×10^3 KJ mol-1
Explanation:
From E= hf
E= Energy of the photon
h= Plank's constant
f= frequency of the radiation
But f= c/λ
c= speed of light
λ= wavelength
Hence
E= hc/λ
E= 6.63×10^-34 × 3×10^8/135×10^-12
E= 147×10^-17 × 6.02×10^23
E= 884.9×10^3 KJ mol-1