Respuesta :

Answer:

Complete factored: (4x+4)(x+1) and 2x(x²-4)

Step-by-step explanation:

We have to check each option one by one

Option 1: [tex]121x^2+36y^2[/tex]

It is sum of two perfect square, As we know sum of two perfect square can't be factored. It is prime equation.

False

Option 2: [tex](4x+4)(x+1)[/tex]

Here we have two factor (4x+4) and (x+1). In both factor degree of x is 1. It is complete factor form.

Complete factor: [tex]4(x+1)(x+1)[/tex]

True

Option 3: [tex]2x(x^2-4)[/tex]

Here we have two factor 4x and x²-4. For second factor it is further factor. Because it is difference of square. Factor of x²-4 = (x+2)(x-2)

Complete Factor: 2x(x+2)(x-2)[/tex]

True

Option 4: [tex]3x^4-15n^3+12n^2[/tex]

Here variable are not same. So, it can't be factor.

False

The completely factored polynomials are [tex]\boxed{2x\left( {{x^2} - 4} \right)}[/tex] and [tex]\boxed{\left( {4x + 4} \right)\left( {x + 1} \right)}[/tex]. Option (b) and option (c) are correct.

Further Explanation:

Given:

The options are as follows,

(a). [tex]121{x^2} + 36{y^2}[/tex]

(b). [tex]\left( {4x + 4} \right)\left( {x + 1} \right)[/tex]

(c). [tex]3{x^4} - 15{n^3} + 12{n^2}[/tex]

(d). [tex]3{x^4} - 15{n^3} + 12{n^2}[/tex]

Calculation:

In option (a)

The expression [tex]121{x^2} + 36{y^2}[/tex] is not in the factored form. option (a) is not correct.

In option (b)

The expression [tex]\left( {4x + 4} \right)\left( {x + 1} \right)[/tex] is in the factored form.

[tex]{\text{Factored}} = 4{\left( {x + 1} \right)^2}[/tex]

Option (b) is correct.

In option (c)

The expression [tex]2x\left( {{x^2} - 4} \right)[/tex] is in the factored form.

[tex]\begin{aligned}{\text{Factored}} &= 2x\left( {{x^2} - 4} \right)\\&= 2x\left( {x + 2} \right)\left( {x - 2} \right)\\\end{aligned}[/tex]

Option (c) is correct.

In option (d)

The expression [tex]3{x^4} - 15{n^3} + 12{n^2}[/tex] is not in the factored form.

Option (d) is not correct.

The completely factored polynomials are [tex]\boxed{2x\left( {{x^2} - 4} \right)}[/tex] and [tex]\boxed{\left( {4x + 4} \right)\left( {x + 1} \right)}.[/tex] Option (b) and option (c) are correct.

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Exponents and Powers

Keywords: solution, factored, completely, polynomial, factorized form, expression, difference of cubes, exponents, power, equation, power rule, exponent rule.

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