Question

1. two positive numbers are in
a ratio of 3:4. the sum of
three times the first and two
times the second is 68. find
the smaller number?
solution​

Answer 1

Answer:

12

Step-by-step explanation:

the ratio of the 2 numbers = 3 : 4 = 3x : 4x ( x is a multiplier ) , then

3(3x) + 2(4x) = 68 , that is

9x + 8x = 68

17x = 68 ( divide both sides by 17 )

x = 4

smaller number = 3x = 3 × 4 = 12