For a gas at 4.5 atm of pressure, the solubility of a gas is 9.5 g/L.
How much gas, in grams, is mathematically given as
s2=8.3782grams
Generally, the equation for the is mathematically given as
Si /S2 √P1/√P2
Therefore
[tex]s2=9.5*\sqrt{3.5}/\sqrt{4.5}[/tex]
s2=8.3782g
In conclusion. The solubility is
s2=8.3782g
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