How is the graph of the parent function, y = StartRoot x EndRoot transformed to produce the graph of y = StartRoot negative 2 x EndRoot? It is translated horizontally by 2 units and reflected over the x-axis. It is translated horizontally by 2 units and reflected over the y-axis. It is horizontally compressed by a factor of 2 and reflected over the x-axis. It is horizontally compressed by a factor of 2 and reflected over the y-axis.

It is given that the two functions one is the parent function [tex]\rm y = \sqrt[3]{-x}[/tex] and the transformed function [tex]\rm y = -0.4 \sqrt[3]{-x-2}[/tex].

It is required to find the transformation rules.

What is a function?

It is defined as a special type of relationship and they have a predefined domain and range according to the function.

We have parent function:

[tex]\rm y = \sqrt[3]{-x}[/tex]

and transformed function:

[tex]\rm y = -0.4 \sqrt[3]{-x-2}[/tex]

If we multiply the parent function with a negative value it will f(x) over the x axis.

By the transformation rules of the function y = -f(x) reflects f(x) over x-axis.

After applying the transformation to the parent function:

[tex]\rm y = -\sqrt[3]{-x}[/tex]

By the transformation rules of the function if multiply the function with less than the unit value it will be compressed by the multiplied factor ie.

y = k f(x) and k<1, the function will be compressed by the k factor hence:

[tex]\rm y = -0.4\sqrt[3]{-x}[/tex] (after applying the second transformation)

As we can see the transformed function is subtracted by -2

By rules of transformation, for y=f(x-A) it would be a horizontal translation of 'A' unit to the right.

After applying this transformation we get:

[tex]\rm y = -0.4 \sqrt[3]{-x-2}[/tex] which is a transformed function derived after applying the transformation to the parent function.

Thus, the parent function will be reflected over the x-axis, compressed by a factor of 0.4, and translated into 2 units right.

Learn more about the function here:

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