Question

A bottle is launched from a bottle launcher. The height of the bottle is modeled by the equation h(t) = –16t2 + 78t + 10. How long does it take the bottle to reach the ground?

A.
10 seconds

B.
5 seconds

C.
4.7 seconds

D.
1.1 seconds

Answer 1

Answer:

C: 4.7

Step-by-step explanation:

Axis of symmetry: -b/2a

a=-16

b=78

-78/2(2(-16))= 4.875 seconds in the air.