Question

A real estate agent is working for a developer who claims that the average commute time to downtown is 20 minutes with a standard deviation of 7 minutes. Stephon is an independent real estate agent and wants to check the times for his client. He took a random sample of 15 commute times and found an average of 26 minutes. He did hypothesis testing using a significance level of 5%. Which conclusion could he make? The z-statistic is 0. 22, so the null hypothesis should not be rejected. The z-statistic is 1. 69, so the null hypothesis should not be rejected. The z-statistic is 3. 32, so the null hypothesis should be rejected. The z-statistic is 3. 67, so the null hypothesis should be rejected.

Answer 1

Answer:

but yea

het 1+11+12

Step-by-step explanation:

Answer 2

We conclude that z-score = 0.0005 which is less than 5%.

To calculate the z-statistic,

We must first calculate the standard error.

What is the formula for standard error?

Standard error is standard deviation divided by the square root of the population.

$standard error=\frac{standard deviation }{\sqrt{population} }$

In this case, it is equal to 1.81.

The z-score is defined the distance from the sample to the population mean in units of standard error.

z = (26 – 20)/1.81 = 3.31

Therefore we conclude that  z-score = 0.0005 which is less than 5%.

To learn more about the z-score visit:

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