Question

please help me with this, I will give brainliest.

find the value of x round to the nearest 10th

Answer 1

$\tan x = \dfrac{\text{Opposite}}{\text{Adjacent}}\\\\\implies \tan x = \dfrac{12}{6}\\\\\implies \tan x = 2\\\\\implies x = \tan^{-1} (2)=63.4^\circ$

Answer 2

Answer:

x ≈ 63.4°

Step-by-step explanation:

using the tangent ratio in the right triangle.

tan x = $\frac{opposite}{adjacent}$ = $\frac{12}{6}$ = 2 , then

x = $tan^{-1}$ ( 2) ≈ 63.4° ( to the nearest tenth )