Question

What is the area of this rectangle?
11.2 cm
5.1 cm

Answer 1

Answer :-

• Area of Rectangle is 57.12 cm² .

Explanation :-

As per the provided information in the given question, we have been given that the Length of Rectangle is 11.2 cm . Its Breadth is given as 5.1 cm . And, we have been asked to calculate the Area of Rectangle .

For calculating the Area , we will use the Formula :-

$\bigstar \: \: \: \boxed {\sf { \: Area \: of \: Rectangle \: = \: Lenght \: \times \: Breadth \: }}$

Therefore , by Substituting the given values in the above Formula :-

$\dag \: \: \: \sf {Area \: of \: Rectangle \: = \: Lenght \: \times \: Breadth}$

$\longmapsto \: \: \: \sf {Area \: of \: Rectangle \: = \: 11.2 \: \times \: 5.1}$

$\longmapsto \: \: \: \textbf {\textsf {Area \: of \: Rectangle \: = \: 57.12 }}$

Hence :-

• Area of Rectangle = 57.12 cm² .

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Additional Information :-

$\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered} \end{gathered} \end{gathered}$

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Answer 2

Given:

• length= 11.2 cm
• width= 5.1 cm

To find:

The area of the given rectangle.

Solution:

$a = length \times width$

$a = 11.2 \times 5.1$

$a = 57.12 \: {cm}^{2}$

Therefore, the area of the given rectangle is 57.12 square centimeters.