Question

Given the equation, what is the center and radius of the circle?

(x-7) ^2 + (Y-4) ^2= 64 ^2

Answer 1

We are given the equation of circle (x - 7)² + (y - 3)² = 64² , but let's recall the standard equation of circle i.e (x - h)² + (y - k)² = r², where (h, k) is the centre of the circle and r being the radius ;

So, consider the equation of circle ;

${:\implies \quad \sf (x-7)^{2}+(y-4)^{2}=(64)^{2}}$

On comparing this equation with the standard equation of Circle, we will get, centre and radius as follows

• Centre = (7, 4)
• Radius = 64 units