Question

Trina purchases 10 tickets from a charity raffle. Each ticket in the raffle has 6 different numbers between the numbers 1 and 20. If there is only one prize, what is the probability of Trina winning the prize? Express your solution as a fraction in reduced form.

Answer 1

The probability of winning when there is only one prize, is:

P = 1/2,790,720

How to find the probability?

Each ticket has 6 different numbers, in order, from 1 to 20.

• The first number has 20 options.
• The second number has 19 options (because the numbers can't repeat).
• The third number has 18 options, and so on.

The total number of possible combinations is given by the product between the numbers of options, so there are:

C = 20*19*18*17*16*15 = 27,907,200 possible tickets.

So, if Trina purchases 10 tickets, she has a probability of 10 out of 27,907,200 winning (when we assume that there is only one prize)

Then the probability is:

P = 10/27,907,200 = 1/2,790,720

If you want to learn more about probability, you can read:

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