The magnitude of the electric field at the dot is : 10⁴ v/m
Given that there are three equipotential lines with equal spacing,we will apply the the relationship between P.D and electric field
Determine the magnitude of the electric field at the dot
change in voltage = E .d
100 - 0 = E * ( 1 * 10⁻² m ) ----- ( 1 )
From equation ( 1 )
The magnitude of E = 100 v / ( 1 * 10⁻² m )
= 10⁴ v/m
Hence we can conclude that The magnitude of the electric field at the dot is : 10⁴ v/m
Learn more about electric field : https://brainly.com/question/14372859
