Respuesta :
[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer}}[/tex]
Let's evaluate ~
[tex]\qquad \sf \dashrightarrow \: \dfrac{1}{3 {}^{ - 2} \times {x}^{ - 4} \times {y}^{2} } [/tex]
plug in the values :
[tex]\qquad \sf \dashrightarrow \: \dfrac{1}{3 {}^{ - 2} \times {3}^{ - 4} \times { - 1}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \dfrac{1}{3 {}^{ - 6} {}^{ } {}^{} } [/tex]
[tex]\qquad \sf \dashrightarrow \: {3}^{6} [/tex]
[tex]\qquad \sf \dashrightarrow \:729[/tex]
Therefore, B is the Correct choice ~
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Answer:
729
Step-by-step explanation:
Given expression:
[tex]\sf \dfrac{1}{3^{-2}x^{-4}y^2}[/tex]
Apply exponent rule [tex]\sf \dfrac{1}{a^{-b}}=a^b[/tex]
[tex]\sf \implies \dfrac{3^2x^4}{y^2}[/tex]
[tex]\sf \implies \dfrac{9x^4}{y^2}[/tex]
Substituting x = 3 and y = -1:
[tex]\sf \implies \dfrac{9(3)^4}{(-1)^2}[/tex]
[tex]\sf \implies \dfrac{9 \cdot 81}1}[/tex]
[tex]\sf \implies 729[/tex]