Question

A neutralization reaction between HCl and NaOH has taken place in the lab, below is the data. Please determine the concentration of the unknown HCl solution. Please make sure all final answers are written using the correct number of significant figures and using scientific notation.

1 HCl + 1 NaOH 1 H2O + 1 NaCl

Molarity of NaOH = 1.00 M

What is the change in volume of NaOH?

Answer 1

From the table showing the data involving the neutralization reaction between HCl and NaOH, the concentration of the HCl solution would be 0.864 M

Titration calculation

From the available data:

Volume of acid used = 0.0351 - 0.0131 = 0.022 L

Volume of base used = 0.0575 - 0.0385 = 0.019 L

Concentration of base = 1.00 M

Number of moles of acid and base = 1

Using the equation:                      CaVa/CbVb = Na/Nb = 1

Ca = 1x0.019/0.022 = 0.864 M

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