Question

A 50kg ball rolls off a building it is going 5 m/s when it hits the ground. How tall is the building

Answer 1

Answer:

1.25m

Step-by-step explanation:

s=ut+1/2gt^2

Newton's second law of motion

F=ma

50x10

500N

500/50

g/a=10m/s^2

u=0m/s

s= 1/2gt^2

v=u+gt

5=0+(10t)

5=10t

t=0.5s

s=0.5×10×(0.5)^2

=1.25m