Question

Which is the equation of the line with slope 3 that contains point (-1,5)?


y-1 = 3(x + 5)
y - 1 = 3(x - 5)
y - 5= 3(x - 1)
y - 5= 3(x + 1)

Answer 1

the answer is y-5=3(x+1)

Answer 2

Answer:

D

$y-5=3(x+1)$

Step-by-step explanation:

We can see that the question is asking for the Point-Slope Form;

$y-y_{1} =m(x-x_{1})$

The points go into the equation for $y_{1}$ and $x_{1}$

$y-5=m[x-(-1)]$

M would be the slope;

$y-5=3[x-(-1)]$

Which basically is:

$y-5=3(x+1)$